Optimal. Leaf size=147 \[ \frac {256 i a^4 \sec ^5(c+d x)}{1155 d (a+i a \tan (c+d x))^{5/2}}+\frac {64 i a^3 \sec ^5(c+d x)}{231 d (a+i a \tan (c+d x))^{3/2}}+\frac {8 i a^2 \sec ^5(c+d x)}{33 d \sqrt {a+i a \tan (c+d x)}}+\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d} \]
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Rubi [A] time = 0.24, antiderivative size = 147, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3494, 3493} \[ \frac {8 i a^2 \sec ^5(c+d x)}{33 d \sqrt {a+i a \tan (c+d x)}}+\frac {64 i a^3 \sec ^5(c+d x)}{231 d (a+i a \tan (c+d x))^{3/2}}+\frac {256 i a^4 \sec ^5(c+d x)}{1155 d (a+i a \tan (c+d x))^{5/2}}+\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d} \]
Antiderivative was successfully verified.
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Rule 3493
Rule 3494
Rubi steps
\begin {align*} \int \sec ^5(c+d x) (a+i a \tan (c+d x))^{3/2} \, dx &=\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d}+\frac {1}{11} (12 a) \int \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)} \, dx\\ &=\frac {8 i a^2 \sec ^5(c+d x)}{33 d \sqrt {a+i a \tan (c+d x)}}+\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d}+\frac {1}{33} \left (32 a^2\right ) \int \frac {\sec ^5(c+d x)}{\sqrt {a+i a \tan (c+d x)}} \, dx\\ &=\frac {64 i a^3 \sec ^5(c+d x)}{231 d (a+i a \tan (c+d x))^{3/2}}+\frac {8 i a^2 \sec ^5(c+d x)}{33 d \sqrt {a+i a \tan (c+d x)}}+\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d}+\frac {1}{231} \left (128 a^3\right ) \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^{3/2}} \, dx\\ &=\frac {256 i a^4 \sec ^5(c+d x)}{1155 d (a+i a \tan (c+d x))^{5/2}}+\frac {64 i a^3 \sec ^5(c+d x)}{231 d (a+i a \tan (c+d x))^{3/2}}+\frac {8 i a^2 \sec ^5(c+d x)}{33 d \sqrt {a+i a \tan (c+d x)}}+\frac {2 i a \sec ^5(c+d x) \sqrt {a+i a \tan (c+d x)}}{11 d}\\ \end {align*}
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Mathematica [A] time = 1.06, size = 109, normalized size = 0.74 \[ \frac {2 a \sec ^4(c+d x) (\cos (d x)-i \sin (d x)) \sqrt {a+i a \tan (c+d x)} (\sin (3 c+2 d x)+i \cos (3 c+2 d x)) (494 \cos (2 (c+d x))+110 i \tan (c+d x)+215 i \sin (3 (c+d x)) \sec (c+d x)+39)}{1155 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.64, size = 125, normalized size = 0.85 \[ \frac {\sqrt {2} {\left (14784 i \, a e^{\left (6 i \, d x + 6 i \, c\right )} + 12672 i \, a e^{\left (4 i \, d x + 4 i \, c\right )} + 5632 i \, a e^{\left (2 i \, d x + 2 i \, c\right )} + 1024 i \, a\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{1155 \, {\left (d e^{\left (10 i \, d x + 10 i \, c\right )} + 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \sec \left (d x + c\right )^{5}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.31, size = 125, normalized size = 0.85 \[ \frac {2 \left (512 i \left (\cos ^{6}\left (d x +c \right )\right )+512 \left (\cos ^{5}\left (d x +c \right )\right ) \sin \left (d x +c \right )-64 i \left (\cos ^{4}\left (d x +c \right )\right )+192 \left (\cos ^{3}\left (d x +c \right )\right ) \sin \left (d x +c \right )-20 i \left (\cos ^{2}\left (d x +c \right )\right )+140 \cos \left (d x +c \right ) \sin \left (d x +c \right )+105 i\right ) \sqrt {\frac {a \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}\, a}{1155 d \cos \left (d x +c \right )^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 21.08, size = 996, normalized size = 6.78 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 7.25, size = 293, normalized size = 1.99 \[ \frac {a\,{\mathrm {e}}^{-c\,1{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,64{}\mathrm {i}}{5\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^2}-\frac {a\,{\mathrm {e}}^{-c\,1{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,192{}\mathrm {i}}{7\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^3}+\frac {a\,{\mathrm {e}}^{-c\,1{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,64{}\mathrm {i}}{3\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^4}-\frac {a\,{\mathrm {e}}^{-c\,1{}\mathrm {i}-d\,x\,1{}\mathrm {i}}\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,64{}\mathrm {i}}{11\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^5} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (i a \left (\tan {\left (c + d x \right )} - i\right )\right )^{\frac {3}{2}} \sec ^{5}{\left (c + d x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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